PROVE THAT
A+B+B+B+80+90=100
Answer is : Akkad Bakkad Bombay Bo assi nabbhe pure 100
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A+B+B+B+80+90=100
(24 votes, average: 3.33 out of 5) (24 votes, average: 3.33 out of 5) (24 votes, average: 3.33 out of 5) (24 votes, average: 3.33 out of 5)
10log(0.1)+20log(0.1)+20log(0.1)+20log(0.1)+80+90=100
10log(0.1)+20log(0.1)+20log(0.1)+20log(0.1)+80+90=100
A = -40 B = -10
(-40) + (-10) + (-10) + (-10) + 80 + 90 = 100
Itna easy ke liye kya Hats of…hehehehe…lols
Akkad bakkad bambe bo 80 90 pure 100
(A+b+b+b)-(80+90)=100 if a=30 b=80
A=20,B=-30 so
20-30-30-30+80+90=100
Smart cookie
(-10)+(-20)+(-20)+(-20)+80+90=100
akkad bakkad bambey bo 80 90 poore 100
Hats off….kya pakda hai
Awesome Sneha…