Number Puzzle #90
A man had Rs.900 and brought some toys with all the money. Out of which 5 toys were defected. He sold all the remaining toys by increasing the price by Rs.2 and made a profit of Rs.80.
What is the no.of initial toys and the initial cost of toys?
Check your answer, Number of Toys:-
Check your answer, Initial Cost:-
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Let assume he had x toys and bought it for Rs.y per piece.
Now, we can form these two equations from these
x*y = 900;//Total cost
(y+2)(x-5) = 900+80;//as he mad profit of Rs.80 by selling x-5 toys in Rs.(y+2).
Now, we can form these two equations from these
x*y = 900;//Total cost
(y+2)(x-5) = 900+80;//as he mad profit of Rs.80 by selling x-5 toys in Rs.(y+2).
xy + 2x -5y -10= 900+80;
2x-5y = 90;
2x-5*900/x = 90
2x^2 -4500 = 90x;
x^2 -45x – 2250 = 0;
(x-75)(x+30) = 0;
x = 75 and x =–30, as number of toys cant be negative, initial number of toys were 75.
Initial Cost = 900/75 = Rs.12.
