Solve this
0 0 0=6
1 1 1 = 6
2 2 2=6
3 3 3 =6
4 4 4=6
5 5 5=6
6 6 6=6
7 7 7=6
8 8 8=6
9 9 9=6
In the space you can use any kind of functions like addition subtraction divison etc
But you cannot bring up new numbers
Eg: 2+2+2=6
0) (0! + 0! + 0!)!
1) (1+1+1)!
2) 2+2+2=6
3) 3×3-3=6
4) 4+4-( square root of 4)=6
5) (5÷5)+5=6
6) 6+6-6=6
7) 7-(7÷7)=6
8) (cube root of 8) + (cube root of 8) + (cube root of 8) = 6
9) (square root of 9)* (square root of 9)- (square root of 9)=6
1) (1+1+1)!
2) 2+2+2=6
3) 3×3-3=6
4) 4+4-( square root of 4)=6
5) (5÷5)+5=6
6) 6+6-6=6
7) 7-(7÷7)=6
8) (cube root of 8) + (cube root of 8) + (cube root of 8) = 6
9) (square root of 9)* (square root of 9)- (square root of 9)=6
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1/2+1/2+1/2=6..
0) (0!+0!+0!)!=6
1) 1!+1!+1!=6
2) 2+2+2=6
3) 3×3-3=6
4) 4+4- square root of 4=6
5)5÷5+5=6
6) 6+6-6=6
7) 7-7÷7=6
8) (square root of ((8/8)+8))! = 6
9) square root of 9 × square root of 9 – square root of 9 =6
Nice and smart for 8.
Ten is like this
(-√(10/10-10))!
i solved ten and yes, 0 can be done like follows:
(0!+0!+0!)!
Remember, the factorial of zero is one!
how to get answers
0)The first one cannot be solved since all digits are zero..!!
1) unable to solve
2) 2+2+2=6
3) 3×3-3=6
4) 4+4- square root of 4=6
5)5÷5+5=6
6) 6+6-6=6
7) 7-7÷7=6
8) cube root of 8 + cube root of 8 + cube root of 8 = 6
9) square root of 9 × square root of 9 – square root of 9 =6
Anyone with the answer of 1 1 1 = 6
similarly (0+0+0)!=6
0+0+0!=1
same….
= (1+1+1)!
= (3)!
= (3*2*1)
= 6
0) (0! + 0! + 0!)! (! Is factorial sign)
1) (1+1+1)!
2) 2+2+2=6
3) 3×3-3=6
4) 4+4-( square root of 4)=6
5)(5÷5)+5=6
6) 6+6-6=6
7) 7-(7÷7)=6
8) (cube root of 8) + (cube root of 8) + (cube root of 8) = 6
9) (square root of 9)* (square root of 9)- (square root of 9)=6
sqrt 9=3
cbrt 8=2