Number Puzzle # 63
If
11 + 11 = 8,
12 + 12 = 12,
13 + 13 = 16
14 + 14 = 20
Then
16 + 16 = ?
Check your answer:- See Explanation
Answer is 28
How?
Right side number is equal to the sum of the digits on left side multiplied by 2
for ex.
11 + 11 => (1+1+1+1)*2
Thus
16 + 16 => (1+6+1+6)*2 = 28.
How?
Right side number is equal to the sum of the digits on left side multiplied by 2
for ex.
11 + 11 => (1+1+1+1)*2
Thus
16 + 16 => (1+6+1+6)*2 = 28.
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11+11=22
2+2=4
4*2=8
12+12 = 24
2+4=6
6*2=12
13+13 =26
2+6=8
8*2=16
14+14=28
2+8=10
10*2=20
Alternatively it can be 10
16+16=32
3+2=5
5*2 = 10
28
i have guessed 28 – but only because it increments with 4 each time. Is there a “deeper” rule?
its sum of each digit X 2
Example of what Sanjay is saying
11+11=8 —– (1+1+1+1)2=8
12+12=12 —- (1+2+1+2)2=12
13+13=16 —- (1+3+1+3)2=16
14+14=20 —– (1+4+1+4)2=20
so
16+16=28 —- (1+6+1+6)2=28
Personally, I found the answer the same way Quasselkasper found it. and I believe that it makes more sense.
For each incremental number, add 4 to the previous answer.
With Sanjay’s explanations
both 5+5 and 14+14 equal 20 which isn’t mathematically sound.
The way Quasselkasper and I found it 5+5=-20
nice one:)