Number Puzzle #121
Number Puzzle #121
If 3/20=1/10+1/20
3/5=1/5+1/5+1/5
Then, 7/10=????
Ans.7/10=1/5+1/2
How?
Trick is to make dividend as 1 in minimum possible additions.
How?
Trick is to make dividend as 1 in minimum possible additions.
so we should try to write 7/10 as 1/x + 1/y + 1/z …..
we can easily see that x = 5, y = 2 will be enough.
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1/5+1/5+1/5+1/10=7/10
1/2+1/10+1/10
Simple one
(1/2+1/5)=7/10
1/5+1/5+1/5+1/10 = (2+2+2+1)/10 =7/10
3/5 + 1/10=7/10
1/5+1/2= (1*2)+(1*5)/5*2 = 7/10