(16 votes, average: 3.88 out of 5)One person has some money in his pocket, He visits four temple on the way.
As soon as he enters a temple, his money gets double and he offers Rs. 100 in each temple. thus his pocket gets empty after he returns from the fourth temple.
How much money he had initially ?
Check your answer:-
Click here to See SolutionWhen he reached 1st temple his money becomes double that means 2*x or 2x. After he leaves 1st temple remaining amount is 2x-100
then after leaving 2nd temple he have [2*(2x-100)]-100 = 4x-300
then after leaving 3rd temple he have [2*(4x-300)]-100 = 8x-700
then after leaving 4th temple he have [2*(8x-700)]-100 = 16x-1500 which should be equal to 0 since he has nothing at the end
So 16x-1500=0
16x=1500
x=1500/16=93.75
OR you can reverse engineer
before the 4th temple he must be having 50, so that it doubles to 100 and offer 100 Rs.
before the 3rd temple he must be having 75 => 150 – 100 => 50 (for 4th temple)
before 2nd temple he must be having 175/2 = 87.5 => 175 -100 => 75 (for 3rd temple)
before 1st temple he must be having 187.5/2 = 93.75=> 187.5 – 100 => 87.5 (for 2nd temple)
93.85
93.75
Yes; It is Rs 93.75; and the process goes like this:
1.93.75×2=187.5-100=87.5
2.87.5×2=175-100=75
3.75×2=150-100=50
4.50×2=100-100=00
How did u find it
Let the person have Rs x with him initially.
When he reached 1st temple his money becomes double that means 2*x or 2x. After he leaves 1st temple remaining amount is 2x-100
then after leaving 2nd temple he have [2*(2x-100)]-100 = 4x-300
then after leaving 3rd temple he have [2*(4x-300)]-100 = 8x-700
then after leaving 4th temple he have [2*(8x-700)]-100 = 16x-1500 which should be equal to 0 since he has nothing at the end
So 16x-1500=0
16x=1500
x=1500/16=93.75
Think backwards, reverse engineering
93.75 rupees
93.75 rs
93.75
yes its 93.75
Try in backwards.
Before u leave 4th temple your amount is 100. Means before you enter amt is 50. Similar ally go backwards.