soln by Sruti

2+5+8= 101621 | 10+16= 26-5=21
2+6+5= 121015 | 12+10= 22-7=15
6+7+8= 424881 | 42+48= 90-9=81
3+6+7= 182128 | 18+21= 39-11=28

Relation between 5,7,9 & 11 is that they have a difference of 2.

As the squirrel climbs 5 feet and comes down by 4 feet every day, she effectively going up by 1 feet every day

So she will climb 20 feet in 20 days, but on the 21st day she will climb 5 feet and will reach the top thus taking a total of 21 days

Its actually simple

logic is first number – half of second number
i.e. 6 -3 = 3
7 -2 = 5
8 -3 = 5
3 -1 = 2

ans is 219 as 7, (7×2)+3=17, (17×3)+3=54, (54×4)+3=219, (219×5)+3=1098, (1098×6)+3=6591
(answered by mugdha)

alternate square or cube minus the number in the series of 1,2,3,4,5,6,7…

(1²-1)=0
(2³-2)=6
(3²-3)=6
(4³-4)=64
(5²-5)=20

Let the person have Rs x with him initially.

When he reached 1st temple his money becomes double that means 2*x or 2x. After he leaves 1st temple remaining amount is 2x-100

then after leaving 2nd temple he have [2*(2x-100)]-100 = 4x-300

then after leaving 3rd temple he have [2*(4x-300)]-100 = 8x-700

then after leaving 4th temple he have [2*(8x-700)]-100 = 16x-1500 which should be equal to 0 since he has nothing at the end

So 16x-1500=0
16x=1500
x=1500/16=93.75

OR you can reverse engineer
before the 4th temple he must be having 50, so that it doubles to 100 and offer 100 Rs.
before the 3rd temple he must be having 75 => 150 – 100 => 50 (for 4th temple)
before 2nd temple he must be having 175/2 = 87.5 => 175 -100 => 75 (for 3rd temple)
before 1st temple he must be having 187.5/2 = 93.75=> 187.5 – 100 => 87.5 (for 2nd temple)

it is the square of 17,18 and 19 in each row

17*17 => 289
18*18 => 324
19*19 => 361

_2_|_6_|_4_
_1_|_5_|_7_
_3_|_8_|_9_
in number’s ko is tarha arrange karein ke jis taraf se bhi add karein ’15’ answer aaye.

Let’s first get the sequences whose sum is 15
1 5 9
1 6 8
2 4 9
2 5 8
2 6 7
3 4 8
3 5 7
4 5 6

Now in order to make diagonal, rows and columns sum to 15, middle element should be present in atleast 4 sequences.
There is only one numbers which is present in four sequences i.e. 5, so 5 will be the middle element.

Now corner number can be the number which is present in atleast three sequences, numbers present atleast in 3 sequences are 2, 4, 6, 8.

Numbers which are present only in two sequences can not be in corners and middle of the matrix, such numbers are 1, 3, 7, 9.

By using above logic, we can create a matrix easily.
_8_|_3_|_4_
_1_|_5_|_9_
_6_|_7_|_2_

Obviously there will be multiple possible answers by rotating the matrix.