Number Puzzles - Page 15 of 25

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If 5 3 2 = 151022

April 5, 2014 by puzzler 9 Comments

Number Puzzle #85
If 5 3 2 = 151022 9 2 4 = 183652 8 6 3 = 482466 5 4 5 = 202541 then 9 5 5 = ?

If 5 3 2 = 151022 9 2 4 = 183652 8 6 3 = 482466 5 4 5 = 202541 then 9 5 5 = ?

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the calculation is like this
9 5 5 =?

9×5 = 45 (first and second)
9×5 = 45 (first and third)
sum of 45+45 =90 and from this deduct center no i.e. 5 =85
hence answer is 454585
Solution is courtesy Jaideep Sandhu, answered in disqus comments

Number Puzzle #84

March 31, 2014 by puzzler 4 Comments

if 532=1561028, 641=244630, 785=564035123 then 821=?

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here the logic is
R1 = first digit * second digit
R2 = second digit * third digit
R3 = third digit * first digit
so final number is

R1R2R3(R1+R2+R3 – second digit)

for 532=1561028
R1 => 5*3 = 15
R2 = 3*2 = 6
R3 = 2*5 = 10

final number = 15610(15+6+10-3) => 1561028

same logic is true for new two numbers as well

by the same logic for 821
R1 = 8*2 = 16
R2 = 2*1 = 2
R3 = 1*8 = 8

final number 1628(16+2+8-2) => 162824

9 temples with 100 steps

March 26, 2014 by puzzler 4 Comments

Number Puzzle #83

9 temples 100 steps puzzle

A person has some money in his pocket. He visits 9 temples on the way, every temple has 100 steps. he puts Rs.1 on each step while going up and as well as while coming back. On each temple he offers half of the money from his pocket to god, that way his pocket gets empty after 9th temple.
How many Rs. he had initially?

–In Hindi–
Ek aadmi kuch paise leke nikalta hai, raaste me 9 mandir hai ,har mandir me 100 sidiya hai, wo har mandir ki sidiyo pe jate waq 1 ..1..rupia rakhta hai, aate waqt bhi 1..1..rupia rakhta hai,…har mandir me jeeb me bache hove aadhe paise deta hai,….is tarah…jab wo akhri mandir se utarta …to us ke paas ke sab paise khatam ho jate hai,…..sawal ye hai .ke wo kitne paise leke nikalta hai…”

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Answer: he had a total of Rs.1,46,900 in his pocket initially.
How? We should start from last temple here.
he offered Rs.100 while coming back so he must have offered Rs.100 to the god on 9th temple and offered Rs.100 while going up on the 9th temple. so he had Rs.300 before 9th temple.

similarly before 8th temple: (300+100)*2 + 100 = 900
similarly before 7th temple: (900+100)*2 + 100 = 2100
similarly before 6th temple: (2100+100)*2 + 100 = 4500, we had some error here in calculating, thanks to our readers for correcting us
similarly before 5th temple: (4500+100)*2 + 100 = 9300
similarly before 4th temple: (9300+100)*2 + 100 = 18900
similarly before 3rd temple: (18900+100)*2 + 100 = 38,100
similarly before 2nd temple: (38100+100)*2 + 100 = 76500
similarly before 1st temple: (76500+100)*2 + 100 = 153300

Couple with 35 sons

March 23, 2014 by puzzler 2 Comments

Number Puzzle #82

A couple went for picnic they have 35 sons each son had seven wives each wife had 5 sons.

How many people went for picnic in total ?

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Answer is 2 as only the couple went to the picnic.

However if we consider everyone went to picnic, here is is answer for that.
Let’s count the people
Couple : 2 people
Their sons: 35
Son’s wives: 35*7
Son’s wives sons: 35*7*5

Total people: 2 + 35 + 35*7 + 35*7*5 = 1507

Beer bottles and friends

March 22, 2014 by puzzler 1 Comment

Number Puzzle #81
A box contains beer bottles if divided between 4 friends 4 bottles are balance and if divided between 5 friends 3 bottles are balance what will be the balance if divided between 7 friends the box contains minimum no of bottles.

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Answer: There will be one extra bottle after dividing between 7 friends.
How?
Let’s say total number of beer bottles in box are x. then we can say

x = 4*m + 4, where m is integer greater than or equal to 0.
x = 5*n + 3, where n is integer greater than or equal to 0.

From above two eequations
4m+4 = 5n + 3 = x
=> 5n – 4m = 1, where m and n are integers greater or equal to 0.
For bottles to be minimum, lets assume m and n are 0
thus from above equation 0 = 1, which is not true, so they cant be both 0 at same time.

If you observe neither of them can be zero at a time, so Now lets take next case where m and n are 1.
5m -4n = 1
5 – 4 = 1
1 = 1, which is true
thus total number of bottles are 5+3 or 4 + 4, i.e. 8
and if divided between 7 friends, 1 bottle will be extra.