Number Puzzle #75
Find missing number in series
Find missing number 18, 46, 94,___,52, 61
Check your answer:-
Click here to See Solutionthis series is 9^2 reverse, 8^2 reverse, 7^2 reverse, 6^2 reverse, 5^2 reverse, 4^2 reverse
18, 46, 94, 63, 52, 16
Number Puzzle #74
Missing number in series 22,26,38,_,74,102
Hint
Check your answer:-
Click here to See SolutionNumber Puzzle #73
Challenge your mind
You entered a bus -in that you saw 7 girls -each girl has 7 bags -in each bag there are 7 big cats. -Each big cat has 7 little cats -each cat has 4 legs.
Calculate the legs in the bus?
IF 1112 = 25,
1113 = 36
1114 = 47
1115 = 58
Then
1117 = ??
Check your answer:-
Click here to See SolutionHow will u divide 1000 one Rs. Coins in ten bag so that u can give any amount between 1-1000 by just giving the bags without changing the no of coins in each bag.
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Its a number.
Divided by 2 the balance should be 1,
by 3 bal 2,
by 4 bal 3,
by 5 bal 4,
by 6 bal 5,
by 7 bal 0,
by 8 bal 7.
Find the number? Understand it properly before answering.
Check your answer:-
Click here to See Solutionhere balance means remainder
in order to solve we know that it should be a perfect multiple of 7 (As the remainder is 0). also we can see that it should end wither with 4 or 9 (since remainder is 4 when divided by 5), we can further remove 4 since remainder should be 1 when divided by 2 (it should be odd number).
now lets list multiples of 7 ending with 9
49 (7×7), 119(17×7), 189(27×7), 259(37×7)
49 is ruled out since remainder is 1 when divided by 8
if you see 119 it satisfied all the condition
119%8 -> 7
119%6 -> 5
119%4 -> 3
119%3 -> 2
One Grand Father, One Father and One Grand Son.
Sum of their age is 140 Years.
Grand Son’s age in month is equal to Grand Father’s age in years.
Grand Son’s age in days is equal to Father’s age in weeks.
What is the Age of all three?
–In Hindi–
Ek Dada Ek Baap Ek Pota 3no Ki Total Age 140 Years Hai Pota jitne Month Ka Dada utne Saal ka Pota jinte din ka Baap utne week ka hai Batao 3no Kitne kinte Saal k Hain?
Click here to see Answer with Solution
Lets assume the age(in years) of Grand Father, Father and Son as GF, F and S respectively.
Sum of their age is 140 Years
=> Equation 1 => GF + F + S = 140
Grand Son’s age in month = Grand Father’s age in years
S*12 = GF => Equation 2=> GF = 12S
Grand Son’s age in days = Father’s age in weeks
S*365 = F*(365/7)
S = F/7 => Equation 3 => F = 7S
Now we have three variables and three equations, we can easily solve it
12S + 7S + S = 140
20s= 140 => S = 7
F = 7S = 49
GF = 12S = 84.
Number Puzzle #68
missing number in 1, 10, 30, ??, 130
Check your answer:-
Click here to See Solution
Actually this is a GP with first element as 1 and variable factor. where the factor comes from this series
1, 3, 7, 13.
Tn = Tn-1 + 2^(n-1);
T1 = 1;
T2 = T1 + 2^(2-1)= 1 + 2 = 3;
T3 = T2 + 2^(3-1) = 3 + 4 = 7;
T4 = T3 + 2^(4-1) = 7 + 6 = 13
nth number in GP = first number * (10)(Tn-1 in series);
First Element in GP = 1;
Second Element in GP(i.e. n = 2) = 1*10*(T1 in series); = 10
Third element in GP(i.e. n =3) = 1*10*(T2 in series) = 1*10*3 = 30
Fourth element in GP (i.e. n =4) = 1*10*(T3 in series) = 1*10*7 = 70
Fifth element in GP (i.e. n =5) = 1*10*(T4 in series) = 1*10*13 = 130
Thus the missing number here is 70.
Number Puzzle #67
If
4+5+4+5=81
5+6+5+6=16
6+7+6+7=64
1+2+1+?=16
What is the missing number?
Thus the patter is sum of the digits till we get single digit and then square of the the single digit.
Method 1:
So lets assume the missing number is x
thus 1+2+1+x = x + 4
Now if x is less then or equal to 5(i.e. x+4 is single digit)
(x+4)(x+4) = 16 => x = 0
Now if x is greater then 5( i.e. x + 4 is two digit number)
lets replace x by 6+y (where y is single digit)
x+4 => 6+y+4 => 10 + y => y +1 => (y+1)*(y+1) = 16 => y = 3
thus x = 6+y = 9.
Note: If we assume missing number can be more then single digit.
Method 2:
its the reverse engineering method => to get 16 the sum of digits should be 4
we already have 1+2+1 = 4 thus missing number can be 0
other ways to get the sum of digits as 4 => 13, i.e. missing number = 13-4 = 9
other ways is 22, i.e. missing number 22-4 = 18
other way is 31, i.e. missing number 31 – 4 = 27
other way is 40, thus missing number 40 -4 = 36
so there can be more such numbers
There are seven thieves, They steal diamonds from a diamond merchant and run away in jungle. While running, night sets in and they decide to rest in the jungle When everybody’s sleeping, two of the best friends get up and decide to distribute the diamonds among themselves and run away. So they start distributing but find that one diamond was extra. So they decide to wake up 3rd one and divide the diamonds again …..only to their surprise they still find one diamond extra. So they decide to wake up fourth one. Again one diamond is spare. 5th woken up……still one extra. 6th still one extra. Now they wake up 7th and diamonds are distributed equally.
How many minimum diamonds they steal?
Check your answer:-
See SolutionNow y should be divisible by 2, 3, 4, 5 and 6, its nothing but common multiple of all.
LCM of 2, 3, 2*2, 5, 2*3 => 2*3*2*5 => 60
at the same time common multiple + 1 should be divisible by 7 as well.
60 + 1 is not divisible by 7
120(60*2) + 1 is not divisible by 7
180(60*3) + 1 is not divisible by 7
240(60*4) + 1 is not divisible by 7
300(60*5) + 1 is divisible by 7
Thus they must have stolen minimum 301 diamonds.
