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Guess the room number

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It was the first day of our second semester and we were looking for our hostel room numbers allotted, we saw that one of our friend was already allotted the room number last night and he challenged us to guess his new room number. We gave following answers

135, 780, 785 and 732.

He said, “That’s amazing”, “You’ve each guessed exactly one digit correctly and in its right place!”

Now can you guess what is his room number ?


See Guess the room number puzzle solution

Answer

Answer is 182

How?

explanation

The first digit must be 1 or 7. It can’t be 7 as only one digit is correct in each guess. So it’s 1.

The other digits in guess #1 (i.e. 3 and 5) must be incorrect. Therefore, from guess #3, the second digit is 8.

Guess #4 has a correct digit which must be its third, i.e. 2.

Shopkeeper and duplicate note

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shopkeeper and duplicate note

shopkeeper and duplicate note

A very simple but confusing puzzle.
A lady buys goods worth Rs.200 from a shop. (shopkeeper is selling the goods with zero profit). The lady gives him Rs.1000 note. The shopkeeper gets the change from the next shop and keeps Rs.200 for himself and returns Rs.800 to the lady. Later the shopkeeper of the next shop comes with the Rs.1000 note saying “duplicate” and takes his money back.
How much LOSS did the shopkeeper face?

Check your answer:-

Tried enough already?


See Shopkeeper and duplicate note solution

Answer

The answer is Rs.1000
How?

Solution 1

To get the loss of shopkeeper we can get the profit lady and the other shopkeeper.

Loss of first shopkeeper = (Profit of the lady + Profit of the second shopkeeper)

Profit of the lady = Rs.200(for goods) + Rs.800(for the change she received) = Rs.1000
Profit of the second shopkeeper = Rs.0(as he got his money back)
So the loss of the shopkeeper is = 1000 + 0 = Rs.1000

Solution 2

Second way of looking at is what shopkeeper gave to others and what is took from others

Loss of the shopkeeper = What he gave to others - what he took.

What he took
From Lady: Nothing(as the note was a duplicate one)
From Second Shopkeeper: Rs.1000
What he gave
To Lady:- Rs.200(goods) + Rs.800(change)
To second shopkeeper: Rs. 1000
So the loss = (200 + 800 + 1000) – (1000) = Rs.1000

Inverted cards puzzle

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inverted cards puzzle

inverted cards puzzle

One fine day, Santa and banta were playing cards, but suddenly power went off and they were getting bored. So santa randomly inverted position of 10 cards out of 52 cards(and shuffled it) and asked banta to divide the card in two pile with equal number of inverted cards(number of cards in each pile need not be equal). It was very dark in the room and banta could not see the cards, after thinking a bit banta divided the cards in two piles and quite surprisingly on counting number of inverted cards in both the piles were equal.
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10 prisoners and hats puzzle

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Their are 10 prisoners in a jail for a minor crime, they all request the jail officer to set them free, jail officer agrees to release them tomorrow, saying i will

  1. Make you all stand in a queue in ascending order of your heights(smallest first).
  2. You will not be allowed to turn your head(they have to look straight)
  3. I will put one hat on your head, either BLACK or WHITE in color.
  4. Everyone of you has to tell the color of his hat starting from the tallest prisoner, you can only say BLACK or WHITE.
  5. You all will be released, if and only if at least 9 of you guess your hat’s color correctly.

Can you suggest a strategy to the prisoners to maximize the chances of their release?

10 prisoners and hats puzzle

10 prisoners and hats puzzle

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Four glasses on a square table

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four glasses on a square table puzzle, also known as the blind bartender’s problem

Four glasses are placed on the corners of a square table. Some of the glasses are upright (up) and some upside-down (down). You have to arrange the glasses so that they are all up or all down (while keeping your eyes closed all the time). The glasses may be re-arranged in turns subject to the following rules.

  1. Any two glasses may be inspected in one turn and after feeling their orientation you may reverse the orientation of either, neither or both glasses.
  2. After each turn table is rotated through a random angle.
  3. At any point of time if all four glasses are of the same orientation a ring will bell

You have to come up with a solution to ensure that all glasses have the same orientation (either up or down) in a finite number of turns. The algorithm must be non-stochastic i.e. it must not depend on luck.
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