Most of us are familiar with google codejam, those who don’t visit https://code.google.com/codejam for more information. This is the first problem from Online Round 1C 2013, top 1000 from this round will be eligible for next online round.

Problem Statement

In English, there are 26 letters that are either vowels or consonants. In this problem, we consider a, e, i, o, and u to be vowels, and the other 21 letters to be consonants.

A tribe living in the Greatest Colorful Jungle has a tradition of naming their members using English letters. But it is not easy to come up with a good name for a new member because it reflects the member’s social status within the tribe. It is believed that the less common the name he or she is given, the more socially privileged he or she is.

The leader of the tribe is a professional linguist. He notices that hard-to-pronounce names are uncommon, and the reason is that they have too many consecutive consonants. Therefore, he announces that the social status of a member in the tribe is determined by its n-value, which is the number of substrings with at least n consecutive consonants in the name. For example, when n = 3, the name “quartz” has the n-value of 4 because the substrings quartz, uartz, artz, and rtz have at least 3 consecutive consonants each. A greater n-value means a greater social status in the tribe. Two substrings are considered different if they begin or end at a different point (even if they consist of the same letters), for instance “tsetse” contains 11 substrings with two consecutive consonants, even though some of them (like “tsetse” and “tsetse“) contain the same letters.
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