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Number Puzzle #32

April 2, 2013 by puzzler Leave a Comment

 

Find the missing number

25 15
100
59 ?

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Answer is 1

Sum of all 4 outer box is 100

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Number Puzzle #31

April 1, 2013 by puzzler 1 Comment

 

IF 1 + 1 = 5 2 + 2 = 20 3 + 3 = 45 Then, 4 + 4 = ?

IF 1 + 1 = 5
2 + 2 = 20
3 + 3 = 45
Then, 4 + 4 = ?

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Answer is 80

How?
Multiply the two numbers and then multiply the result by 5.

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Number Puzzle #30

April 1, 2013 by puzzler 2 Comments

 

16, 43, 27 11, 36, 25 29, 56, ?

16, 43, 27
11, 36, 25
29, 56, ?

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Missing number is 27.

How?
Number in middle column is sum of the respective numbers in first and third column. thus the missing number should be 56 – 29 = 27.

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Find a pythagorean triplet from an array

March 28, 2013 by puzzler 1 Comment

Problem Statement:
Given an array a of n integers find all possible Pythagorean triplets from the array.

What is Pythagorean triplet?

A Pythagorean triple consists of three positive integers a, b, and c, such that a2 + b2 = c2. this formula is derived from Pythagoras theorem: “For every right angle triangle with side lengths a, b, and c=> a2 + b2 = c2“.

Pythagorean Triplet

Pythagorean Triplet

Solution:
[Read more…]

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Number Puzzle #29

March 28, 2013 by puzzler 1 Comment

IF 1 = 3 2 = 6 3 = 9 4 = 12 Then, 5 = ?

IF 1 = 3
2 = 6
3 = 9
4 = 12
Then, 5 = ?

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Answer is 15

How?
Its simple, just multiply the number by 3.

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Number Puzzle #28

March 28, 2013 by puzzler 12 Comments

 

IF 1+2 = 3 3 + 4 = 21 5 + 6 = 55 Then 4 + 5 = ?

IF 1+2 = 3
3 + 4 = 21
5 + 6 = 55
Then 4 + 5 = ?

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Answer is 36

Explanation:
1 + 2 => (1)^2 + (1*2) = 3
3 + 4 => (3)^2 + (3*4) = 21
5 + 6 => (5)^2 + (5*6) = 55
Thus 4 + 5 => (4)^2 + (4*5) = 36

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3 SUM problem

March 27, 2013 by puzzler Leave a Comment

Problem Statement:
Given a set S of n integers find all possible subsets(a,b,c) such that a + b + c = 0.

Solution:
Brute force approach is of O(n^4) but we can solve it in O(n^2) by using the approach in Non duplicate pairs that sum to S.

First sort the array(Order O(nlogn)), than finding a, b, c pairs is equal to finding=> For every element a in the array, if there exists a pair with sum equal to -a. As explained in Non duplicate pairs that sum to S, we can get the pair with sum -a in O(n) and we have to repeat this exercise n times so order of complexity will be O(n^2).

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Number Puzzle #27

March 27, 2013 by puzzler 1 Comment

 

13, 25, ? 16, 28, 35 19, 31, 28

13, 25, ?
16, 28, 35
19, 31, 28
What is the missing number.

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Answer is 32

How?
If you see the rows every next number = previous number in the row +3.

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Number Puzzle #26

March 27, 2013 by puzzler Leave a Comment

 

Find the missing number

Find the missing number

This puzzle is courtesy , shared on puzzlersworld facebook page.
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Answer is 2

How?
7*6 = 4 2
9*9 = 8 1
5*3 = 1 5
6*2 = 1 2

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Number Puzzle #25

March 21, 2013 by puzzler 1 Comment

 

Whats the missing number in the triangle

Whats the missing number in the triangle

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Answer is 125

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