**A train is going at a speed of 60kmph towards Delhi ****and returned back at a speed of 30kmph. What is its average ****speed?**

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We will go with this simple formula to calculate average speed of the train

Average Speed = (Total Distance/Time Taken);

Lets assume the distance traveled by train in one direction is x, and time taken while going towards delhi is t1, while it took t2 time while coming back from Delhi.

We can say

x/t1 = 60

x/t2 = 30

Total Average speed = 2x/(t1 + t2)

average speed = 2x /(x/60+x/30) = (2x/90x)*60*30 = 40

Nisha says

40KMPH

HVG says

Let the distance between Place to Delhi be X.

So the total distance distance = X+X = 2X

Now time taken for first travel from A to Delhi = X/60 hours

Time taken while coming from Delhi to A = X/30 hours

Total time taken for the to and fro journey = (X/60) + (X/30) hours = (3X/60) hours

Average speed = Total Distance / Total Time

= (2X) / (3X/60) KMPH

This gives X = 40 KMPH

Answer = 40KMPH

Prabhakar Singh says

40 kmph using formula 2xy/(x+y)

nitin says

45 kmph

Rony Saha says

40kmph