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How many runs a single player can score in One day match (50 overs/ 300 balls)… No ‘no balls’, no wides, no extras, no over throws.

**So how much runs he can score max?**

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Here we will assume ideal and little practical scenario. we will assume that batsman can not run for more that 3 runs in a ball, as otherwise there is no limit, he can run infinite runs(theoritically) in a ball, as far as opposite team does not catch the ball.

Thus an opening batsman can score 5 six in continuous 5 balls and then go for 3 runs, these 3 runs on last ball will ensure that he changes the side so that will face the first ball of the next over.

thus in an over he can score maximum of 5*6 + 3 = 33 runs, so in 50 overs 50*33 = 1650runs.

However there is a catch, in last ball of the match, he need not go for 3 runs, he can hit six, thus maximum runs can be scored by a batsman in a one day cricket match can be 1653.

Akshay says

However here we have to also consider that after every over, the batsman will change his position. So theoretically, the no. of runs should be multiplied by 25 and not 50.

Prasad Kumar says

1653 is ok but what about hitting the helmet and scoring 5 runs off last ball of every over and changing strike also possible

puzzlersworld says

that will not be counted as his runs

prashant says

i want to know there is any limit run score on single delivery without 6 & 4 (by running he will take 1,2,3,4,5,6 ….. what is the rule) please comments

puzzlersworld says

Lets be practical, else by that logic a plaer can make infinite runs in single ball, why only 5,6,7 or 8, why not 100 in one ball ?

Tushar Kumar says

lets be practical, no one can hit sixes every ball. think about it. hypothetically every thing is possible ðŸ™‚

hdfuial says

who gives a shit

vijay says

On an ideal scenario a person cannot run for a five (unless its an overthrow), so I guess the answer would be 1653 and not 1751…

Abizer says

Is there any rule which says Batsman can only run maximum 5 runs or 3 runs?

lohith says

If batsman got duck out mnz? Wtf!!! 1st ball of the innings

Priyang says

Correct Answer is 1751

He will hit six on first 5 balls of every over and will take 5 runs on last ball to get the strike till 49th over. In last over he will hit 6 sixes.

Anthoniraj Sanjeeviraj says

Hi Frnd this is Antoniraj S

The correct answers is That would be 1653 runs. If he hits first 5 balls of an over for 5 sixes and scores 3 runs of the last ball( to retain strike)…and scores 6 sixes of the last over(as he doest need to retain strike now) , that would make a calculation like…

49*5*6+49*3+6*6 = 1653 runs

CA Jimit Shah says

1653

Venky says

a single player can play more than 25 overs because he can take single in every last ball of the over and again he gets strike again in the next over…

panky says

1653

rahul says

(30+3)*49 + 36=1653

Ajay Nair says

Ok, assuming he is changing strike on last ball. So for all 49 overs he takes a 3 to retain the strike. ie 33 * 49 overs + last over he hits 6 sixes so total is 1653 runs

Mubashir Aziz says

Correct Answer is 1653

He will hit six on first 5 balls of every over and will take 3 runs on last ball to get the strike till 49th over. In last over he will hit 6 sixes. So he will face hit sixes on 251 balls =251×6=1506 and score 3 runs on 49 balls 49X3=147 So Total score is 1653

Rocky says

251*6+49*3 = 1653

niral says

No 900 is wrong.. suppose x and y are playing.. x is the opening bats man. He plays the first over. from the second over y plays the first ball nd gives the batting to x.. so like this x will face 6 balls in first nd from second over he will face 5 balls per over that means 251 balls. Nd if he takes six runs per ball his score will be 1506. My name is Niral Vipin Mehta.. Sudan

puzzlersworld says

he can play 6 balls in the last over as well.. but still there are other ways he can make more runs

John Steven says

50*31 = 1550

Rajender Singh says

1500

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