x1 + x2 + x3 = 9

x4 + x5 + 5 = 12

x7 + x8 + x9 = 7

x1 + x4 + x7 = 6

x2 + x5 + x8 = 9

x3 + 5 + x9 = 13

x1 + x5 + x9 = 5

x7 + x5 + x3 = 11

7 variables and 7 equations, its little tough and cumbersome to solve these equations so lets try some hit and trial.

you can see that x1 + x5 + x9 is only 5, thus it has less number of possibilities for x1, x5 and x9 as these cant be -ve.

lets assume x1 and x9 both are 0, in that case x5 will be 5.

17

0 1 8 9

2 5 5 12

4 3 0 7

——

6 9 13 5

diagonal equation does not satisfy, we can see x7 + x5 + x3 exceeds by 6.

so lets try to reduce it by 6,

lets try by x1 = 1, x9 = 1

11

1 1 7 9

4 3 5 12

1 5 1 7

6 9 13 5

it satisfies all the conditions

so, x1 = 1 , x2 = 1, x3 = 7, x4 = 4, x5 = 3, x7 = 1, x8 =5 and x9 = 1

amitk says

1 1 7

4 3 5

1 5 1