Number Puzzle #109
IF 1 2 3 = 45
2 3 3 = 64
3 2 1 = 39
8 4 0 = 72
Then
1 1 1 = ?
Check your answer:-
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123 = 2×23 – 1 = 46 – 1 = 45
233 = 2×33 – 2 = 66 – 2 = 64
321 = 2X21- 3 = 42 – 3 = 39
840 = 2X40 – 8 = 80 -8 = 72
So
111 = 2X11 – 1 = 22 -1 = 21
233 = 2×33 – 2 = 66 – 2 = 64
321 = 2X21- 3 = 42 – 3 = 39
840 = 2X40 – 8 = 80 -8 = 72
So
111 = 2X11 – 1 = 22 -1 = 21
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but 840=71 which is given. And both answers are noy satisfying this point.
there was a typo in image description, corrected it, it is 840 = 72..
☻☺ lol, answers are NOY, lol ☺☻
Logic is : – twice of last 2 digits miuns left most digit.
123 = 2×23 – 1 = 46 – 1 = 45
233 = 2×33 – 2 = 66 – 2 = 64
321 = 2X21- 3 = 42 – 3 = 39
840 = 2X40 – 8 = 80 -8 = 72
So
111 = 2X11 – 1 = 22 -1 = 21
Simpler version of @drksoni solution… Thanks !!!
Answer is 21
logic is as follows:
(((number formed by second and third digit) – first digit) +number formed by second and third digit)
(1). 1 2 3 [ ( 23 – 1 = 22 + 23 ) = 45 ]
(2). 2 3 3 [ ( 33 – 2 = 31 + 33 ) = 64 ]
(3). 3 2 1 [ ( 21 – 3 = 18 + 21 ) = 39 ]
(4). 8 4 0 [ ( 40 – 8 = 32 + 40 ) = 72 ]
Therefore
(5). 1 1 1 [ ( 11 – 1 = 10 + 11) = 21 ]
You Cracked it !!!
Thanks Sir.
Sale khud hi dal ke khud hi answer kr rahe hai