Kids Maths Puzzles

One zero after every 10 numbers, thus 20 + 10 extra (for 100’s series, 100, 101 to 109) + 1 extra for 200
Thus total number of zeros between 1 to 200 are 31.

If we try to make equations

x1 + x2 + x3 = 9

x4 + x5 + 5 = 12

x7 + x8 + x9 = 7

x1 + x4 + x7 = 6

x2 + x5 + x8 = 9

x3 + 5 + x9 = 13

x1 + x5 + x9 = 5

x7 + x5 + x3 = 11

7 variables and 7 equations, its little tough and cumbersome to solve these equations so lets try some hit and trial.

you can see that x1 + x5 + x9 is only 5, thus it has less number of possibilities for x1, x5 and x9 as these cant be -ve.

lets assume x1 and x9 both are 0, in that case x5 will be 5.

17
0 1 8 9
2 5 5 12
4 3 0 7
——
6 9 13 5

diagonal equation does not satisfy, we can see x7 + x5 + x3 exceeds by 6.
so lets try to reduce it by 6,

lets try by x1 = 1, x9 = 1
11
1 1 7 9
4 3 5 12
1 5 1 7
6 9 13 5

it satisfies all the conditions
so, x1 = 1 , x2 = 1, x3 = 7, x4 = 4, x5 = 3, x7 = 1, x8 =5 and x9 = 1

Lets assume that he offers x flowers at every temple, thus he must have only x flowers left at the end of 3rd temple, otherwise he will not have zero flowers at the end of fourth river.

also we can say that after offering flowers at second temple he should be left with x/2 flowers.
similarly after offering flowers at first temple he should be left with (3x/2)/2 flowers.
Thus he should be carrying (x + 3x/4)/2 flowers initially, i.e. 7x/8 flowers initially.

For number of flowers to be integer, x =8, thus he must carry 7 flowers initially and offer 8 flowers at each temple.

Here as there are no braces, operators will work as per their precedence.
division and multiplication has same precedence and addition and subtraction has same precedence. Also / and * has higher precedence then + and -.
Thus first % and * should operate, now they being of the same precedence, they will work from left to right order thus % will operate first and the * will work on its result.

Thus 36%6*3 -9 +1 => 6*3 -9 +1 => 18 -9 + 1=> 10