See Answer

### Answer with Explanation

Answer is 108.

**How?**

2 + 3 = 2 *(2+3) = 10

8 + 4 = 8*(8+4) = 96

7 + 2 = 7*(7+2) = 63

6 + 5 = 6*(6+5) = 66

9 + 3 = 9*(9+3) = 108

See AnswerHide Answer

Answer is 108.

**How?**

2 + 3 = 2 *(2+3) = 10

8 + 4 = 8*(8+4) = 96

7 + 2 = 7*(7+2) = 63

6 + 5 = 6*(6+5) = 66

9 + 3 = 9*(9+3) = 108

See AnswerHide Answer

Answer is 3.

**How?**

It simple, but you have to think more then the math ðŸ™‚

1 = one = 3 letters

2 = two = 3 letters

3 = three = 5 letters

4 = four = 4 letters

5 = five = 4 letters

6 = six = 3 letters

See AnswerHide Answer

Answer is 16.

**How?**

Its a little trickier one then others.

sqr root(64) * 5 = 40

sqr root(81) * 7 = 63

sqr root(16) * 4 = ? = 16.

See AnswerHide Answer

Answer is 6.

**How?**

It is the simple subtraction as we used to do in our early maths classes in our childhood, so just reminds us of those days of taking carry and subtracting.

See AnswerHide Answer

Answer is 9.

**How?**

Here, every element in second row = corresponding column element in first row * 2.

Similarly every element in third row = corresponding column element in first row * 3.

See AnswerHide Answer

Answer is 30.

**How?**

Sum of the numbers on vertices of a triangle should be 90, i.e. 20 + 40 + ? = 90 => ? = 30.

See AnswerHide Answer

Answer is 6.

**How?**

Here, Number in a block is sum of the number on the top and right block so 7 = 1 + ?, hence ? should be 6.

**How?**

Let’s say the smallest triangle side is 1 cms, then

**Number of triangles with side 1cms**: 12(3+4+3+2 upward facing) + 12(downward facing)

**Number of triangles with side 2cms**: 6(3+2+1 upward facing) + 6(downward facing)

**Number of triangles with side 3cms**: 1(upward facing) + 1(downward facing)

**How?**

Let’s say the smallest triangle side is 1 cms, then

**Number of triangles with side 1cms**: 10(1+2+3+4 upward facing) + 6(0+1+2+3 downward facing)

**Number of triangles with side 2cms**: 6(1+2+3 upward facing) + 1(downward facing)

**Number of triangles with side 3cms**: 3(upward facing)

**Number of triangles with side 4cms**: 1(upward facing)

Again it is good to use symmetry here, we can brake this image into six small triangles each formed by one of the side of the hexagon and each of the triangle is divided in half by a line. we will count the number of triangles formed by each part and by taking two or more such parts together.

**Number of triangles formed by one part:** 3 so total 3*6 = **18**.

**Number of triangles formed by taking two adjacent parts together:** 2*3(three such cases as for 3 cases it is zero) so total** 6**.

**Number of triangles formed by taking three adjacent triangles:** 2*6 ( for each case 2 triangles are possible) so total **12**

**Number of triangles formed by taking 4 or 5 parts together:** 0

**Number of triangles formed by taking all 6 parts together:** **1**

- « Previous Page
- 1
- …
- 65
- 66
- 67
- 68
- 69
- …
- 71
- Next Page »