
Find the missing section
Find the missing section
IF 11 = 20
12 = 31
13 = 42
14 = 53
Then 18 = ?
Answer is 97.
How?
11 => (1+1)(1-1) => 20
12 => (2+1)(2-1) => 31
13 => (3+1)(3-1) => 42
14 => (4+1)(4-1) => 53
similarly
18 => (8+1)(8-1) => 97
IF 5 + 3 = 28
9 + 1 = 810
8 + 6 = 214
5 + 4 = 19
then 7 + 3 = ???
Answer is 410.
How?
5 + 3 = (5-3)(5+3) = 28
9 + 1 = (9-1)(9+1) = 810
8 + 6 = (8-6)(8+6) = 214
similarly
7 + 3 = (7-3)(7+3) = 410
IF
2 + 3 = 10
8 + 4 = 96
7 + 2 = 63
6 + 5 = 66
then 9 + 3 = ?
Answer is 108.
How?
2 + 3 = 2 *(2+3) = 10
8 + 4 = 8*(8+4) = 96
7 + 2 = 7*(7+2) = 63
6 + 5 = 6*(6+5) = 66
9 + 3 = 9*(9+3) = 108
IF
1 = 3
2 = 3
3 = 5
4 = 4
5 = 4
then 6 = ?
Answer is 3.
How?
It simple, but you have to think more then the math 🙂
1 = one = 3 letters
2 = two = 3 letters
3 = three = 5 letters
4 = four = 4 letters
5 = five = 4 letters
6 = six = 3 letters
64 5 40
81 7 65
16 4 ?
Answer is 16.
How?
Its a little trickier one then others.
sqr root(64) * 5 = 40
sqr root(81) * 7 = 63
sqr root(16) * 4 = ? = 16.
6 3 2
-3 ? 5
———-
2 6 7
Answer is 6.
How?
It is the simple subtraction as we used to do in our early maths classes in our childhood, so just reminds us of those days of taking carry and subtracting.
1 2 3
2 4 6
3 6 ?
Answer is 9.
How?
Here, every element in second row = corresponding column element in first row * 2.
Similarly every element in third row = corresponding column element in first row * 3.
50
20 40
90
30 10
?
Answer is 30.
How?
Sum of the numbers on vertices of a triangle should be 90, i.e. 20 + 40 + ? = 90 => ? = 30.
4
6 2
9 3 1
19 10 7 ?
Answer is 6.
How?
Here, Number in a block is sum of the number on the top and right block so 7 = 1 + ?, hence ? should be 6.