**Number Puzzle #183**

## Simplr Math Puzzle

## Number Puzzle #181

## Number Puzzle #181

If

2×3=15

2×5=20

2×7=30

2×11=?

## McDonald’s Number Puzzle

**What will be the value Burger + FrenchFries x ColdDrink ?**

Check your answer:-

**Answer**: 15

**Solution**:

If you see there are 3 variables and 3 equations, we can solve the equations and get the variables values and than we can find the value of fourth equation.

From the first equation we can say that ColdDrink = 10

than from the second Burger = (20 – 10)/2 = 5

and from the third equation FrenchFries= (9 – 5)/4 = 1

Thus Burger + FrenchFries * ColdDrink = 5 + 1*10 = 15

here as per BODMAS 5 + 1*10 will be 5 + 10 = 15

## 1 , 17 , 98 , 354 , ?

## Number Puzzle #180

What will be the next number in this series?

1 , 17 , 98 , 354 , ?

Check your answer:-

Click here to See SolutionIf you see the difference between the numbers

16, 91, 256

2^4, 3^4, 4^4

next difference should be 5^4 i.s. 625, thus the next number should be 354+625 => 979

## -1¹²¹-1¹²² -1¹²³-1¹²⁴ =?

-1¹²¹ -1¹²² -1¹²³ -1¹²^⁴ =?

Check your answer:-

Click here to See Solutionbut in this equation power is on 1 not -1

-1¹²¹-1¹²² -1¹²³-1¹²^⁴ = -1-1-1-1 = -4

## complete the series 11,15,19,18,26,21,32, 24,37,__ __

## Number Puzzle #179

What will be the next number in this series?

11,15,19,18,26,21,32, 24,37,____

Check your answer:-

**Next number**

**Next to next number**

Answer With Explanation

First is 11,19,26,32,37 & second is 15,18,21,24

first series is AP with a decreasing difference

11 -> 19 => 8

19 -> 26 => 7

26 -> 32 => 6

32 -> 37 => 5

thus next number should be 37 + 4 => 41

second series is AP with a difference of 3

15, 18, 21, 24 => next number should be 27

## İf 1*36=36, 8*23=23 Then 9*10=?

If 1*36=36

8*23=23

8*67=1

Then

9*10=?

## Number Puzzle #177

## Find next number in following sequence

## What will be the next number in below sequence?

0, 1, 5, 19, 65, 211, ?

Check your answer:-

explanation:

it follows this equation

**3^n – 2^n**where n is integer starting from 0

thus

3^0 – 2^0 = 1 – 1 = 0

3^1 – 2^1 = 3 – 2 = 1

3^2 – 2^2 = 9 – 4 = 5

3^3 – 2^3 = 27 – 8 = 19

3^4 – 2^4 = 65

3^5 – 2^5 = 211

3^6 – 2^6 = 729 – 64 = 665

There is one more way to solve this

**3*previous number + 2^(n-1)**

0x3+1=1;

1×3+2=5;

5×3+4=19;

19×3+8=65;

65×3+16=211;

211×3+32=665;

**wondering how it is possible?**

lets solve 3*previous number + 2^(n-1)

=> 3*(3^(n-1) – 2^(n-1)) + 2^(n-1)

=> 3^n – (2+1)*2^(n-1) + 2^(n-1)

=> 3^n – 2^n – 2^(n-1) + 2^(n-1)

=> 3^n – 2^n i.e. our first equation

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