Can you solve this Math Equation?
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Answer With ExplanationX%y = X*y/100 = (200/y)*(y/100) = 2
If we do 1 push up repetition per day, 3 sets, then increase it by one rep per week for same three sets, how many push ups will we be doing in 6months?
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Answer With Solutionnumber of push ups in first week 3*7 = 21
so total number of push ups in 25 weeks = 21 + 21*2 + 21*3 …. 21*25
its an arithmetic progression with a1 = 21 and d = 21
its Sum = n(a1+an)/2 = 25(21 + 21*25)/2 = 21*25*26/2 = 6825
Push ups done in 5 days = 21*26*5/7 = 26*15 = 390
Total push ups in 6 months = 6825 + 390 = 7215.
jane, ali and pat each planted a tree 90cm in height . in the time it took jane’s tree to grow by 1 cm, ali’s tree grow by 2 cm. by the time it took ali tree to grow by 2cm pat tree grow by 3 cm . how tall was jane tree when pat tree was 108 cm in height.
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Answer With SolutionAnswer: 96cm
Solution: let’s say jane’s tree grow by 1cm in X time, and in the same time ali’s tree grow by 2cm and pat’s tree grow by 3cm.
so to grow 108 – 90 = 18 cm, pat’s tree should take 18/3 = 6X time and jane’s tree should grow by 6cm in the same time.
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Answer With SolutionAnswer: 4
Solution:
You might want to solve it simply like this
First equation: Football + Football + Football = 18 => Football = 18/3 = 6
Second Equation: Wall Clock= 9/3 = 3
Third Equation: Table Fan * Table Fan – Table Fan = 6 => (Table Fan) x (Table Fan – 1) = 6
from 3×2 = 6 => Table Fan = 3
Thus Wall Clock x Football – Table Fan = 3 x 6 – 3 = 15
BUT, if you look carefully, it is not a simple math equation puzzle, football in last equation is different than other, wall clock in 4th equation having different time than the ones in second equation, similarly table fan has 2 blades than 3.
So how do we solve it?
In the first equation black marks on Football are 6, therefore Football value is : 6
In the Second equation clock shows 3pm.. so clock value is 3
In the third equation, table fan has 3 blades, thus having a value of 3, OR you can say a table fan with 3 blades has value 3, thus with 2 blades should have a value 2.
In last equation clock is 2 and Football marks are 3, and table fan has 2 blades
thus 2×3 -2 = 4
Solution by : Ranjan Bala Jain over the mail
Can you tell what will be the sum of the fourth row ?
i.e. Sum of Burger + Beer Bottle * Beer Mug ?
obviously you have to apply some mathematics here, question is how fast you can solve it.
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Solution:
If you see there are 3 variables and 3 equations, we can solve the equations and get the variables values and than we can find the value of fourth equation.
From the first equation we can say that Beer Bottle = 10
than from the second Burger = (20 – 10)/2 = 5
and from the third equation Beer Mug = (9 – 5)/4 = 1
Thus Burger + Beer Mug * Beer Bottle = 5 + 1*10 = 15
here as per BODMAS 5 + 1*10 will be 5 + 10 and not 6*10
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Click here to See Solutionfollowing are the distances:
3rd mansion is 60km apart from the 1st mansion.
4th mansion is 40km apart from the 2nd mansion.
3rd mansion is 10km nearer to the 4th mansion than it is to the 2nd mansion.
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Click here to See SolutionLets draw the diagram first
From above diagram we can write this equation
x+10 + x = 40 => 2x = 30 => x = 15
thus distance between 1st and 4th mansion is 60 + x = 75 km
If Apple + Apple + Apple = 30
Apple + Bananas + Bananas = 18
banana + coconuts = 2
Then coconut + apple + bananans = ?
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Click here to See Solution4B – 2C = 2
2C = 2 => C = 1
C + A + 3B = 1 + 10 + 3 = 14
Click here to See Answer
There are 10 parking spaces numbered from 101 to 110. At least one car is parked in these slots. If cars can be parked only at the consecutively numbered parking slots, how many such arrangements can be made. Consider that only one car can be parked in one parking slot and all cars are identical.
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Click here to See Solutionif you go on like this, number of ways of parking 10 cars in 10 slots = 1
thus total possible arrangements = 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 +1 = 10*11/2 = 55
