Distribute 1 to 99 in five groups so that total of each group comes same & what is that?
One guy had a habit of spending the money as per the day of the month, for example he will spend $18 on 18th of the month.
Once he spent, $63 in continuous 5 days, What could be the dates ?
What was the first day ?Click here to See Solution
lets assume all the days were of the same month, in that case
x + (x+1) + (x+2) + (x+3) + (x+4) = 63
5x = 53
x is coming out to be in decimal, which can not be
now the other possibility is such that month changes after some days
thus there can be few possibilities
A) x + (x+1) + (x+2) + (x+3) + 1 = 63
4x = 56 => x = 14, but 1st cant come after 17th, so it is ruled out
B) x + (x+1) + (x+2) + 1 + 2 = 63
3x = 57 => x = 19, but again 1st cant come after 21, so it is ruled out as well
C) x + (x+1) + 1 + 2 + 3 = 63
2x = 56 => x = 28, this is possible for the month with 29 days, i.e. February of leap year
so thee dates were 28,29,1,2,3
0 6 12 _ 24 30 _ _ 48 _
1 9 _ 24 36 _ _ 56 _ _
Click here to See Answers
For second: put your answers in comments
?One grand father
?One Grand Son
Sum of their ages is 140 years
Grand son’s age in month
is equal to grand fathers age in years
Grand son’s age in days
is equal to Father’s age in weeks
Now, Find out the age of all three.
Check your answer:-
Grand son’s age in years
Father’s age in years
Grand father’s age in yearsClick here to See Answers
G+F+S = 140
S*12 = G
S*365 = (F*365)/7 => F = 7S
Than 12S + 7S + s = 140 => 20S = 140 => S = 7 Years
F = 49 Years
G = 84 Years
A lady starts from her house with some money to visit four Churches.
1. As soon as she enters Church1 her money gets doubled. She donates $100 and moves.
2. At Church2 again her money is doubled and she donates $100.
3. Her money is doubled again at Church3 and she donates $100.
4. At Church4 again her money gets doubled. She donates $100 again and returns home empty handed…
How much money she had when she started from her house???
Check your answer:-Click here to See Solution
Money before church 3: 150/2 = $75
Money before church 2: 175/2 = $87.5
Money before Church 1: 187.5/2 = $93.75
Puzzle Time challenge?
Chalo solve karo…
Its a 5 digit number where…
1st digit denotes how many zeroes are there in the number
2nd digit denotes how many ones are there in the number
3rd digit denotes how many twos are there in the number
4th digit denotes how many threes are there in the number
5th digit denotes how many fours are there in the number
Can you guess the number?
Click here to See Solution
Check your answer:-
Now lets say there 3 0’s then number can be 30010, but thus also violates, 2nd digit tells number of 1’s
Now if there are 2 0’s then 21200 satisfies all the conditions.
A man buy 3 accessories with 100 rupees. first one 5 rupees, second one 3 rupees, third one 0.5 rupees each. he bought total 100 pieces. How many pieces he bought for each accessory ?
Third AccessoryClick here to See Solution
Then we can make these two equations
Eq1: x + y + z = 100
Eq2: 5x + 3y + 0.5z = 100
2*Eq2 => 10x + 6y + z = 200
2*Eq2-Eq1 => 9x + 5y = 100
from this equation x should be a multiple of 5, for x = 5 => y = 11
for x = 10 => y = 2
for x = 15 or more y becomes -ve
So two possible answers
x = 5, y = 11, z = 84
x = 10, y = 2, z = 88